5x^2+40x-385=0

Solution for 5x^2+40x-385=0 equation:

5x^2+40x-385=0

a = 5; b = 40; c = -385;
Δ = b2-4ac
Δ = 402-4·5·(-385)
Δ = 9300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9300}=\sqrt{100*93}=\sqrt{100}*\sqrt{93}=10\sqrt{93}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(40)-10\sqrt{93}}{2*5}=\frac{-40-10\sqrt{93}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(40)+10\sqrt{93}}{2*5}=\frac{-40+10\sqrt{93}}{10}
$